Valid Anagram LeetCode Solution | Easy Approach

Valid Anagram Given two strings s and t, return true if t is an anagram of s, and false otherwise.

An Anagram is a word or phrase formed by rearranging the letters of a different word or phrase, typically using all the original letters exactly once.

Example 1:

Input: s = "anagram", t = "nagaram"
Output: true

Example 2:

Input: s = "rat", t = "car"
Output: false

Constraints:

• 1 <= s.length, t.length <= 5 * 104
• s and t consist of lowercase English letters.

Valid Anagram Solutions

✅Time: O(n)
✅Space: O(128)=O(1)

C++

class Solution {
 public:
  bool isAnagram(string s, string t) {
    if (s.length() != t.length())
      return false;

    vector<int> count(128);

    for (const char c : s)
      ++count[c];

    for (const char c : t)
      if (--count[c] < 0)
        return false;

    return true;
  }
};

Java

 class Solution {
  public boolean isAnagram(String s, String t) {
    if (s.length() != t.length())
      return false;

    int[] count = new int[128];

    for (final char c : s.toCharArray())
      ++count[c];

    for (final char c : t.toCharArray())
      if (--count[c] < 0)
        return false;

    return true;
  }
}

Python

  class Solution:
  def isAnagram(self, s: str, t: str) -> bool:
    if len(s) != len(t):
      return False

    dict = Counter(s)

    for c in t:
      dict[c] -= 1
      if dict[c] < 0:
        return False

    return True

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