# Same Tree LeetCode Solution | Easy Approach

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Given the roots of two binary trees `p` and `q`, write a function to check if they are the same or not.

Two binary trees are considered the same if they are structurally identical, and the nodes have the same value.

Example 1:

```Input: p = [1,2,3], q = [1,2,3]
Output: true
```

Example 2:

```Input: p = [1,2], q = [1,null,2]
Output: false
```

Example 3:

```Input: p = [1,2,1], q = [1,1,2]
Output: false
```

Constraints:

• The number of nodes in both trees is in the range `[0, 100]`.
• `-104 <= Node.val <= 104`

Time: O(n)
Space: O(h)

### C++

``````class Solution {
public:
bool isSameTree(TreeNode* p, TreeNode* q) {
if (!p || !q)
return p == q;
return p->val == q->val &&
isSameTree(p->left, q->left) &&
isSameTree(p->right, q->right);
}
};
``````

### Java

`````` class Solution {
public boolean isSameTree(TreeNode p, TreeNode q) {
if (p == null || q == null)
return p == q;
return p.val == q.val &&
isSameTree(p.left, q.left) &&
isSameTree(p.right, q.right);
}
}

``````

### Python

``````class Solution:
def isSameTree(self, p: Optional[TreeNode], q: Optional[TreeNode]) -> bool:
if not p or not q:
return p == q
return p.val == q.val and \
self.isSameTree(p.left, q.left) and \
self.isSameTree(p.right, q.right)

``````

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