Given the roots of two binary trees p
and q
, write a function to check if they are the same or not.
Two binary trees are considered the same if they are structurally identical, and the nodes have the same value.
Example 1:


Input: p = [1,2,3], q = [1,2,3] Output: true
Example 2:


Input: p = [1,2], q = [1,null,2] Output: false
Example 3:


Input: p = [1,2,1], q = [1,1,2] Output: false
Constraints:
- The number of nodes in both trees is in the range
[0, 100]
. -104 <= Node.val <= 104
Same Tree Solutions
✅Time: O(n)
✅Space: O(h)
C++
class Solution {
public:
bool isSameTree(TreeNode* p, TreeNode* q) {
if (!p || !q)
return p == q;
return p->val == q->val &&
isSameTree(p->left, q->left) &&
isSameTree(p->right, q->right);
}
};
Java
class Solution {
public boolean isSameTree(TreeNode p, TreeNode q) {
if (p == null || q == null)
return p == q;
return p.val == q.val &&
isSameTree(p.left, q.left) &&
isSameTree(p.right, q.right);
}
}
Python
class Solution:
def isSameTree(self, p: Optional[TreeNode], q: Optional[TreeNode]) -> bool:
if not p or not q:
return p == q
return p.val == q.val and \
self.isSameTree(p.left, q.left) and \
self.isSameTree(p.right, q.right)
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