886. Possible Bipartition LeetCode Solution | Easy Approach

Minimum Cost to Merge Stones

Possible Bipartition We want to split a group of n people (labeled from 1 to n) into two groups of any size. Each person may dislike some other people, and they should not go into the same group.

Given the integer n and the array dislikes where dislikes[i] = [ai, bi] indicates that the person labeled ai does not like the person labeled bi, return true if it is possible to split everyone into two groups in this way.

Example 1:

Input: n = 4, dislikes = [[1,2],[1,3],[2,4]]
Output: true
Explanation: group1 [1,4] and group2 [2,3].

Example 2:

Input: n = 3, dislikes = [[1,2],[1,3],[2,3]]
Output: false

Example 3:

Input: n = 5, dislikes = [[1,2],[2,3],[3,4],[4,5],[1,5]]
Output: false


  • 1 <= n <= 2000
  • 0 <= dislikes.length <= 104
  • dislikes[i].length == 2
  • 1 <= dislikes[i][j] <= n
  • ai < bi
  • All the pairs of dislikes are unique.

Possible Bipartition Solutions

Time: O(n)
Space: O(n)


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