Longest Substring Without Repeating Characters Leetcode Solution

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Longest Substring Without Repeating Characters | Given a string s, find the length of the longest substring without repeating characters.

Example 1:

Input: s = "abcabcbb"
Output: 3
Explanation: The answer is "abc", with the length of 3.

Example 2:

Input: s = "bbbbb"
Output: 1
Explanation: The answer is "b", with the length of 1.

Example 3:

Input: s = "pwwkew"
Output: 3
Explanation: The answer is "wke", with the length of 3.
Notice that the answer must be a substring, "pwke" is a subsequence and not a substring.

Constraints:

  • 0 <= s.length <= 5 * 104
  • s consists of English letters, digits, symbols and spaces.

Solutions

Time: O(n)
Space: O(128)=O(1)

C++

class Solution {
 public:
  int lengthOfLongestSubstring(string s) {
    int ans = 0;
    vector<int> count(128);

    for (int l = 0, r = 0; r < s.length(); ++r) {
      ++count[s[r]];
      while (count[s[r]] > 1)
        --count[s[l++]];
      ans = max(ans, r - l + 1);
    }

    return ans;
  }
};

Java

class Solution {
  public int lengthOfLongestSubstring(String s) {
    int ans = 0;
    int[] count = new int[128];

    for (int l = 0, r = 0; r < s.length(); ++r) {
      ++count[s.charAt(r)];
      while (count[s.charAt(r)] > 1)
        --count[s.charAt(l++)];
      ans = Math.max(ans, r - l + 1);
    }

    return ans;
  }
}

Python

class Solution:
  def lengthOfLongestSubstring(self, s: str) -> int:
    ans = 0
    count = Counter()

    l = 0
    for r, c in enumerate(s):
      count[c] += 1
      while count[c] > 1:
        count[s[l]] -= 1
        l += 1
      ans = max(ans, r - l + 1)

    return ans

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