# Integer to Roman Leetcode Solution | Easy Approach Share:

Integer to Roman | Roman numerals are represented by seven different symbols: `I``V``X``L``C``D` and `M`.

```Symbol       Value
I             1
V             5
X             10
L             50
C             100
D             500
M             1000```

For example, `2` is written as `II` in Roman numeral, just two one’s added together. `12` is written as `XII`, which is simply `X + II`. The number `27` is written as `XXVII`, which is `XX + V + II`.

Roman numerals are usually written largest to smallest from left to right. However, the numeral for four is not `IIII`. Instead, the number four is written as `IV`. Because the one is before the five we subtract it making four. The same principle applies to the number nine, which is written as `IX`. There are six instances where subtraction is used:

• `I` can be placed before `V` (5) and `X` (10) to make 4 and 9.
• `X` can be placed before `L` (50) and `C` (100) to make 40 and 90.
• `C` can be placed before `D` (500) and `M` (1000) to make 400 and 900.

Given an integer, convert it to a roman numeral.

Example 1:

```Input: num = 3
Output: "III"
Explanation: 3 is represented as 3 ones.
```

Example 2:

```Input: num = 58
Output: "LVIII"
Explanation: L = 50, V = 5, III = 3.
```

Example 3:

```Input: num = 1994
Output: "MCMXCIV"
Explanation: M = 1000, CM = 900, XC = 90 and IV = 4.
```

Constraints:

• `1 <= num <= 3999`

Time: O(1)
Space: O(1)

### C++

``````class Solution {
public:
string intToRoman(int num) {
const vector<pair<int, string>> valueSymbols{
{1000, "M"}, {900, "CM"}, {500, "D"}, {400, "CD"}, {100, "C"},
{90, "XC"},  {50, "L"},   {40, "XL"}, {10, "X"},   {9, "IX"},
{5, "V"},    {4, "IV"},   {1, "I"}};
string ans;

for (const auto& [value, symbol] : valueSymbols) {
if (num == 0)
break;
while (num >= value) {
num -= value;
ans += symbol;
}
}

return ans;
}
};
``````

### Java

``````class Solution {
public String intToRoman(int num) {
final int[] values = {1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1};
final String[] symbols = {"M",  "CM", "D",  "CD", "C",  "XC", "L",
"XL", "X",  "IX", "V",  "IV", "I"};
StringBuilder sb = new StringBuilder();

for (int i = 0; i < values.length; ++i) {
if (num == 0)
break;
while (num >= values[i]) {
num -= values[i];
sb.append(symbols[i]);
}
}

return sb.toString();
}
}

``````

### Python

``````class Solution:
def intToRoman(self, num: int) -> str:
valueSymbols = [(1000, 'M'), (900, 'CM'),
(500, 'D'), (400, 'CD'),
(100, 'C'), (90, 'XC'),
(50, 'L'), (40, 'XL'),
(10, 'X'), (9, 'IX'),
(5, 'V'), (4, 'IV'),
(1, 'I')]
ans = []

for value, symbol in valueSymbols:
if num == 0:
break
count, num = divmod(num, value)
ans.append(symbol * count)

return ''.join(ans)

``````

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