Fraction to Recurring Decimal LeetCode Solution | Easy Approach

Fraction to Recurring Decimal Given two integers representing the numerator and denominator of a fraction, return the fraction in string format.

If the fractional part is repeating, enclose the repeating part in parentheses.

If multiple answers are possible, return any of them.

It is guaranteed that the length of the answer string is less than 104 for all the given inputs.

Example 1:

Input: numerator = 1, denominator = 2
Output: "0.5"

Example 2:

Input: numerator = 2, denominator = 1
Output: "2"

Example 3:

Input: numerator = 4, denominator = 333
Output: "0.(012)"

Constraints:

• -231 <= numerator, denominator <= 231 - 1
• denominator != 0

Fraction to Recurring Decimal Solutions

✅Time: O(n)
✅Space: O(1)

C++

class Solution {
 public:
  string fractionToDecimal(int numerator, int denominator) {
    if (numerator == 0)
      return "0";

    string ans;

    if (numerator < 0 ^ denominator < 0)
      ans += "-";

    long n = labs(numerator);
    long d = labs(denominator);
    ans += to_string(n / d);

    if (n % d == 0)
      return ans;

    ans += '.';
    unordered_map<int, int> seen;

    for (long r = n % d; r; r %= d) {
      if (seen.count(r)) {
        ans.insert(seen[r], 1, '(');
        ans += ')';
        break;
      }
      seen[r] = ans.size();
      r *= 10;
      ans += to_string(r / d);
    }

    return ans;
  }
};

Java

 
 class Solution {
  public String fractionToDecimal(int numerator, int denominator) {
    if (numerator == 0)
      return "0";

    StringBuilder sb = new StringBuilder();

    if (numerator < 0 ^ denominator < 0)
      sb.append("-");

    long n = Math.abs((long) numerator);
    long d = Math.abs((long) denominator);
    sb.append(n / d);

    if (n % d == 0)
      return sb.toString();

    sb.append(".");
    Map<Long, Integer> seen = new HashMap<>();

    for (long r = n % d; r > 0; r %= d) {
      if (seen.containsKey(r)) {
        sb.insert(seen.get(r), "(");
        sb.append(")");
        break;
      }
      seen.put(r, sb.length());
      r *= 10;
      sb.append(r / d);
    }

    return sb.toString();
  }
}

Python

class Solution:
  def fractionToDecimal(self, numerator: int, denominator: int) -> str:
    if numerator == 0:
      return '0'

    ans = ''

    if (numerator < 0) ^ (denominator < 0):
      ans += '-'

    numerator = abs(numerator)
    denominator = abs(denominator)
    ans += str(numerator // denominator)

    if numerator % denominator == 0:
      return ans

    ans += '.'
    dict = {}

    remainder = numerator % denominator
    while remainder:
      if remainder in dict:
        ans = ans[:dict[remainder]] + '(' + ans[dict[remainder]:] + ')'
        break
      dict[remainder] = len(ans)
      remainder *= 10
      ans += str(remainder // denominator)
      remainder %= denominator

    return ans

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