# 690. Employee Importance LeetCode Solution | Easy Approach Share:

Employee Importance You have a data structure of employee information, including the employee’s unique ID, importance value, and direct subordinates’ IDs.

You are given an array of employees `employees` where:

• `employees[i].id` is the ID of the `ith` employee.
• `employees[i].importance` is the importance value of the `ith` employee.
• `employees[i].subordinates` is a list of the IDs of the direct subordinates of the `ith` employee.

Given an integer `id` that represents an employee’s ID, return the total importance value of this employee and all their direct and indirect subordinates.

Example 1:

```Input: employees = [[1,5,[2,3]],[2,3,[]],[3,3,[]]], id = 1
Output: 11
Explanation: Employee 1 has an importance value of 5 and has two direct subordinates: employee 2 and employee 3.
They both have an importance value of 3.
Thus, the total importance value of employee 1 is 5 + 3 + 3 = 11.
```

Example 2:

```Input: employees = [[1,2,],[5,-3,[]]], id = 5
Output: -3
Explanation: Employee 5 has an importance value of -3 and has no direct subordinates.
Thus, the total importance value of employee 5 is -3.
```

Constraints:

• `1 <= employees.length <= 2000`
• `1 <= employees[i].id <= 2000`
• All `employees[i].id` are unique.
• `-100 <= employees[i].importance <= 100`
• One employee has at most one direct leader and may have several subordinates.
• The IDs in `employees[i].subordinates` are valid IDs.

Time: O(n)
Space: O(n)

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