**Delete and Earn ** You are given an integer array `nums`

. You want to maximize the number of points you get by performing the following operation any number of times:

- Pick any
`nums[i]`

and delete it to earn`nums[i]`

points. Afterwards, you must delete**every**element equal to`nums[i] - 1`

and**every**element equal to`nums[i] + 1`

.

Return *the maximum number of points you can earn by applying the above operation some number of times*.

**Example 1:**

Input:nums = [3,4,2]Output:6Explanation:You can perform the following operations: - Delete 4 to earn 4 points. Consequently, 3 is also deleted. nums = [2]. - Delete 2 to earn 2 points. nums = []. You earn a total of 6 points.

**Example 2:**

Input:nums = [2,2,3,3,3,4]Output:9Explanation:You can perform the following operations: - Delete a 3 to earn 3 points. All 2's and 4's are also deleted. nums = [3,3]. - Delete a 3 again to earn 3 points. nums = [3]. - Delete a 3 once more to earn 3 points. nums = []. You earn a total of 9 points.

**Constraints:**

`1 <= nums.length <= 2 * 10`

^{4}`1 <= nums[i] <= 10`

^{4}

### Delete and Earn Solutions

✅**Time:** O(n)

✅**Space:** O(n)

**C**++

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